MS Access SQL - distinct records and count of related values

Question

I'm running into a problem with an aggregate query. I've got two tables, MainA and MainC. I want to select only unique values in MainA and then count the number of matches to those values from MainC. I don't care (for now) about values that show up in MainC that aren't in MainA. I've got a simple expression mostly working, which is here:

SELECT DISTINCT TBMainA.Field1, Count(TBMainC.MCField1) AS CountOfMCField1
FROM TBMainA 
LEFT JOIN TBMainC ON TBMainA.Field1 = TBMainC.MCField1
GROUP BY TBMainA.Field1;

However, the problem is that if more than value shows up in MainA, the expression is double-counting the values in MainC (presumptively because there are two cases in MainA to count from). I suspect this has to do with where I'm starting the aggregation or how I'm grouping, but I've banged my head on this one for a bit and haven't produced a working solution yet. Here's some sample data along with the query output as it stands now (MAID and MCID are keys for each table):

MainA

MAID	Field1
1	apples
2	oranges
3	grapefuit
4	peppers
5	kiwi fruit
6	tomatoes
8	avocado
9	bananas
10	apples

MainC

MCID	MCField1
1	bananas
2	peppers
3	peppers
4	tomatoes
5	apples
6	spinach
7	kale
8	apples
9	oranges

Query output:

Field1	CountOfMCField1
apples	4
avocado	0
bananas	1
grapefuit	0
kiwi fruit	0
oranges	1
peppers	2
tomatoes	1

Suggestions welcomed, and thanks for your help...!

Answer 1

For your particular query, this would look like:

SELECT TBMainA.Field1, COUNT(TBMainC.MCField1) AS CountOfMCField1
FROM (SELECT DISTINCT TBMainA.Field1, TBMainC.MCField1
      FROM TBMainA LEFT JOIN
           TBMainC
           ON TBMainA.Field1 = TBMainC.MCField1
     ) as AC
GROUP BY TBMainA.Field1;