I have a docx file in a blob storage.
What I try to do is to get the link/path or url of the file in the blob to apply this function:
def get_docx_text(path):
"""
Take the path of a docx file as argument, return the text in unicode.
"""
document = zipfile.ZipFile(path)
xml_content = document.read('word/document.xml')
document.close()
tree = XML(xml_content)
paragraphs = []
for paragraph in tree.getiterator(PARA):
texts = [node.text
for node in paragraph.getiterator(TEXT)
if node.text]
if texts:
paragraphs.append(''.join(texts))
text = '\n\n'.join(paragraphs)
return (paragraphs,text)
In the parameter path of def get_docx_text(path) I would like to put the path of the file.
How can I do this?
I tried something like this but doesn't work:
from azure.storage.blob import BlobServiceClient, BlobClient, ContainerClient
connection_string='...'
blob_service_client = BlobServiceClient.from_connection_string(connection_string)
service_client = BlobServiceClient.from_connection_string(connection_string)
client = service_client.get_container_client("name_container")
bc = client.get_blob_client(blob="bronze/txt_name.docx")
with open("txt_name.docx", 'wb') as file:
data = bc.download_blob()
file.write(data.readall())
Thank You Gaurav for providing your suggestion in the comment, converting it as answer to help other community member.
Issue: ResourceNotFoundError: The specified blob does not exist
.
Solution: Please try with this code
bc = client.get_blob_client(blob="sink/bronze/txt_name.docx")
Since you're downloading the blob in the same folder where your code is running, you just have to specify the name with which you're saving the file.
For example:in this code
with open("txt_name.docx", 'wb') as file:
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