I have a script and it's display show's upload progress by writing to the same console line. When the script is run from a cron job, rather than writing to a single line, I get many lines:
*** E0710091001.DAT *** [0.67%]
*** E0710091001.DAT *** [1.33%]
*** E0710091001.DAT *** [2.00%]
*** E0710091001.DAT *** [2.66%]
*** E0710091001.DAT *** [3.33%]
*** E0710091001.DAT *** [3.99%]
*** E0710091001.DAT *** [4.66%]
*** E0710091001.DAT *** [5.32%]
*** E0710091001.DAT *** [5.99%]
*** E0710091001.DAT *** [6.65%]
*** E0710091001.DAT *** [7.32%]
*** E0710091001.DAT *** [7.98%]
*** E0710091001.DAT *** [8.65%]
*** E0710091001.DAT *** [9.32%]
*** E0710091001.DAT *** [9.98%]
*** E0710091001.DAT *** [10.65%]
*** E0710091001.DAT *** [11.31%]
*** E0710091001.DAT *** [11.98%]
*** E0710091001.DAT *** [12.64%]
*** E0710091001.DAT *** [13.31%]
*** E0710091001.DAT *** [13.97%]
*** E0710091001.DAT *** [14.64%]
*** E0710091001.DAT *** [15.30%]
*** E0710091001.DAT *** [15.97%]
*** E0710091001.DAT *** [16.63%]
*** E0710091001.DAT *** [17.30%]
*** E0710091001.DAT *** [17.97%]
*** E0710091001.DAT *** [18.63%]
I just want to know if I can tell from inside the script if it's being called from cron, and if so, I won't display this output.
you could create a flag. Possibly undocumented that your cron job would pass to the utility to structure the output.
我将检查sys.stderr.isatty()
-这样一来,无论何时用户无法立即感知到stderr,都可以避免无用的“装饰”输出。
See code below. Replace my print statements with what you want to show.
import sys
if sys.stdout.isatty():
print "Running from command line"
else:
print "Running from cron"
You want to check if you're on a terminal or not. See this stack overflow question: How to detect if my shell script is running through a pipe?
一种简单的方法是让脚本采用一个参数,该参数表示抑制该输出,并在您从cron调用它时提供该参数。
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