Consider this example:
export function fn(arg: string): void;
export function fn(arg: number): void;
export function fn(arg: any) {
console.log(arg);
}
So, fn
can be called either with a string, or a number.
fn('hello!');
fn(42);
So far, so good. But then fn
is executed in a different place:
function fn2(arg2: string | number) {
fn(arg2);
}
In this case TypeScript complains:
No overload matches this call. Overload 1 of 2, '(arg: string): void', gave the following error.
Argument of type 'string | number' is not assignable to parameter of type 'string'. Type 'number' is not assignable to type 'string'. Overload 2 of 2, '(arg: number): void', gave the following error. Argument of type 'string | number' is not assignable to parameter of type 'number'. Type 'string' is not assignable to type 'number'.ts(2769)
index.tsx(3, 17): The call would have succeeded against this implementation, but implementation signatures of overloads are not externally visible.
Can someone help me understand what's going on here?
You can add another overload
export function fn(arg: string): void;
export function fn(arg: number): void;
export function fn(arg: any): void;
export function fn(arg: any) {
console.log(arg);
}
fn('hello!');
fn(42);
function fn2(arg2: string | number) {
fn(arg2);
}
Overloads aren't the same as Union Types. Overloads define 'separate' functions while unions allow you to put different types as arguments.
// fails
function fn2(arg2: string | number) {
fn(arg2); // uses the union type
}
// works
function fn3(arg2: string | number) {
if(typeof arg2 === 'string') {
return fn(arg2); // uses string
}
return fn(arg2); // uses number
}
This means fn2
searches for a function declaration that has an argument of type string|number
while fn3
searches for either a function with type string
or a function with type number
as its first argument.
You should not use any
if you exactly know, which type you want as a function parameter.
See the documentation for Union Types
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