Get data from another table by just comparing the id using php

Question

I want to get data from another table by just calling if the ID and data from another table is the same.

Table_1

Id  | name | lastname

1   | Fred | Moore

---

Table 2

Id  | table1_id 

1    |    1

I can already get and store the table 1 id to my table 2, but i want to echo the name and lastname from the table 1.

eg if table 2 table1_id is equal to Table_1 Id it will print the name and lastname.

Answer 1

Try this query

select table_1.name, table_1.lastname
from table_1
left join on table_2 on table_1.id = table_2.table1_id

Answer 2

<?php

$a = "Table_1";
$b = "Table_2 ";

$allItem = $cxn->query("SELECT * 
FROM $a  
INNER JOIN $b
ON $a.id = $b.id
WHERE $a.id  = 1);

$allItem = $allItem->fetchAll();

$lastName = $allItem["lastname"];
$name = $allItem["name"];

?>

Maybe it could work!

Answer 3

<?php 
$conn = mysqli_connect("localhost","username","password","database_name");
if(!$conn){
echo "Database Connection Failed!";
}

$query1 = mysqli_query($conn,"SELECT table1_id,first_name,last_name FROM table_1")or trigger_error(mysqli_error($conn));
if(mysqli_num_rows($query1)){
while($row1 = mysqli_fetch_array($query1)){
    $table1_id = $row1['table1_id'];
    $table1_first_name = $row1['first_name'];
    $table1_last_name = $row1['last_name'];

    $query2 = mysqli_query($conn,"SELECT table2_id,table1_id,first_name,last_name FROM table_2 WHERE table1_id='$table1_id' ORDER BY first_name,last_name ASC")or trigger_error(mysqli_error($conn)); //check table1_id from table2 AND table1_id from table1 if matched
    $row2 = mysqli_fetch_array($query2);
    $table2_first_name = $row2['first_name'];
    $table2_last_name = $row2['last_name'];

    echo "First Name: ".$table2_first_name."<br>"; //print first name
    echo "Last Name: ".$table2_last_name."<br>"; //print last name
  }
}
else{
echo "No Result Found.";
}
?>