How to print out the access right from linux kernel module

Question

When I run the command lsof from a terminal, it will show a detail list of all file descriptor with a header is FD. And FD column numbers like 1u is actual file descriptor and followed by u,r,w of it's mode as:

• r for read access
• w for write access
• u for read and write access

My question is how to print out these types of access from a linux kernel module? I am able to print the files_path (See the attracted picture). And I see in here that has f_mode in the file struct and tried to print it out and received big numbers, like 1208647709 or 917507

The results after running dmesg

Here is my code

struct task_struct *task_list;
struct fdtable *        fdt = NULL;
unsigned int process_count = 0;
int fd_i;
char  tmpbuf[256];
char * process_path = "";
struct path files_path;
unsigned int mode_path;
char *cwd;
for_each_process(task_list) {
    pr_info("Process: %s\t PID:[%d]\t State:%s\n", 
            task_list->comm, task_list->pid,
            get_task_state(task_list->state));
    if (task_list->files == NULL) continue; 
    fdt = files_fdtable(task_list->files);
    int i=0;
    while(fdt->fd[i] != NULL) { 
        files_path = fdt->fd[i]->f_path;
        mode_path = fdt->fd[i]->f_mode;
        cwd = d_path(&files_path,buf,100*sizeof(char));
        printk(KERN_INFO "Open file with fd %d  %s **mode: %d**", i,cwd, mode_path);            
        i++;
    }
}

Could someone review and support me about this problem? Thanks in advanced

Answer 1

Solution from Tsyvarev: extract both flags using f_mode & (FMODE_READ | FMODE_WRITE). Then switch for the result of that expression:

1. Result equal to FMODE_READ means "r".
2. Result equal to FMODE_WRITE means "w".
3. Result equal to expression FMODE_READ | FMODE_WRITE means "u".