I have two collections.defaultdict
and trying to remove values from d1
that are also in d2
.
from collections import Counter, defaultdict
d1 = Counter({'hi': 22, 'bye': 55, 'ok': 33})
d2 = Counter({'hi': 10, 'hello': 233, 'nvm': 96})
Ideal result:
d3 = set()
d3 = ({'bye':55, 'ok':33})
So far I have tried:
d3 = set()
d3 = d1 - d2
print(d3)
Counter({'bye': 55, 'ok': 33, 'hi': 12})
But this keeps the same value of 'hi'
even though I want to remove all similar ones.
Since, d1
and d2
are Counter
objects they implement subtraction different than sets.
From
collections.Counter
(emphasis mine):Addition and subtraction combine counters by adding or subtracting the counts of corresponding elements .
From
set.difference
orset - other
:Return a new set with elements in the set that are not in the others.
That said, you can use Counter.keys
and use difference
just like sets.
keys = d1.keys() - d2.keys()
# keys = {'bye', 'ok'}
out = {k: d1[k] for k in keys}
# out = {'bye': 55, 'ok': 33}
Use a dictionary comprehension
d3 = {k: v for k, v in d1.items() if k not in d2}
print(d3)
Result:
{'bye': 55, 'ok': 33}
trying to remove values from
d1
that are also ind2
for k in d2:
d1.pop(k, None)
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