I have a dataset like the below dataset. I want to find the number of nights each id was occupied per month. For some rows, the check-in and checkout dates are in different months. I want to know how to write a query to have the occupancy per month. For example, for id=1, check-in: 2020-01-26 and checkout date: 2020-03-02. How can I have a table that shows January occupancy: 6, Feb occupancy: 29, and March occupancy: 1
id | check-in | checkout |
---|---|---|
1 | 2020-01-26 | 2020-03-02 |
first, you need a numbers table
or tally table
, after you can easily to it using this query :
select c.id,
case when m.id <> 0
then adddate(last_day(adddate(checkin_date, interval m.id -1 month)),interval 1 day)
else checkin_date
end as Checkin_date,
case when last_day(adddate(checkin_date, interval m.id month)) > checkout_date
then checkout_date
else last_day(adddate(checkin_date, interval m.id month))
end checout_date,
datediff(case when last_day(adddate(checkin_date, interval m.id month)) > checkout_date
then checkout_date
else last_day(adddate(checkin_date, interval m.id month)) end,
case when m.id <> 0
then last_day(adddate(checkin_date, interval m.id -1 month))
else adddate(checkin_date, interval -1 day) end
) daysdiff
from checkins c
join numbers m on m.id <= period_diff(date_format(checkout_date, "%Y%m"),date_format(checkin_date, "%Y%m"))
order by c.id, checkin_date
this is works for any gap (for more than 1 year)
db<>fiddle here
Requirement is very wide but I will try to assist you.
If I understand correctly, you want month-wise aggregated result of occupied inventory.
You can try below query as base query then add more criteria logic based on your need
select month(check_in), sum(dayofyear(check_out) - dayofyear(check_in)) as 'occupied_days'
from inventory
where year(check_in)=year(check_out)
group by 1;
Above query will work only for dataset where check_in & check_out happened within same year.
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