I am trying to get users name but Flutter gives this error:
The body might complete normally, causing 'null' to be returned, but the return type is a potentially non-nullable type.
Try adding either a return or a throw statement at the end.
Method:
String getUserNameFromUID(String uid) {
FirebaseFirestore.instance
.collection('users')
.where('uid', isEqualTo: uid)
.get()
.then((QuerySnapshot querySnapshot) {
querySnapshot.docs.forEach((doc) {
return doc["name"];
});
});
}
How can I solve my problem? if I add return 0 to end of the method it always gives 0.
It always gives 0.(I do not want 0, I want get user name from uid)
String getUserNameFromUID(String uid) {
FirebaseFirestore.instance
.collection('users')
.where('uid', isEqualTo: uid)
.get()
.then((QuerySnapshot querySnapshot) {
querySnapshot.docs.forEach((doc) {
return doc["name"];
});
});
return "0";
}
First your function should return a Future<String>
since it relies on firestore's get
wich also returns a future. Also docs
is a list, you have to return just one. The first one i guess. In the UI just use a FutureBuilder
Future<String> getUserNameFromUID(String uid) async {
final snapshot = await FirebaseFirestore.instance
.collection('users')
.where('uid', isEqualTo: uid)
.get();
return snapshot.docs.first['name'];
}
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