Is it possible to infer a function argument from another argument? I want to infer 2nd argument based on inference of 1st argument.
Current code
export type GetSlickEventType<T> =
T extends (infer U)[] ? U :
T extends (...args: any[]) => infer U ? U :
T extends SlickEvent<infer U> ? U : T;
export type GetEventType<T> = T extends infer U ? U : T;
type Handler<H> = (e: SlickEventData, data: GetSlickEventType<H>) => void;
export interface SlickEventHandler<T = any> {
subscribe: (slickEvent: SlickEvent<T>, handler: Handler<T>) => SlickEventHandler<T>;
unsubscribe: (slickEvent: SlickEvent<T>, handler: Handler<T>) => SlickEventHandler<T>;
unsubscribeAll: () => SlickEventHandler<T>;
}
and this allows me to do the following
const onHeaderCellRenderedHandler = this.grid.onHeaderCellRendered;
(this._eventHandler as SlickEventHandler<GetSlickEventType<typeof onHeaderCellRenderedHandler >>).subscribe(onHeaderCellRenderedHandler , (e, args) => {
args.column;
});
and this does proper inference
However, what I really wish to do is through a much simpler approach shown below (however below args
is infered as any
)
this._eventHandler.subscribe(onHeaderCellRenderedHandler, (_e, args) => {
const column = args.column;
const node = args.node;
});
So as I mentioned in the question, for that to work, I would need to infer first argument and somehow make an alias that can be used by the second argument. Is that possible with latest version of TypeScript?
I think you want the methods to be generic not the interface, so you would put the generic at the function definition not the interface name.
export interface SlickEventHandler {
subscribe: <T>(slickEvent: SlickEvent<T>, handler: Handler<T>) => SlickEventHandler<T>;
unsubscribe: <T>(slickEvent: SlickEvent<T>, handler: Handler<T>) => SlickEventHandler<T>;
// it is unclear how you would expect a generic to be actually typed on unsubscribeAll
unsubscribeAll: () => SlickEventHandler<unknown>;
}
then the generic will be inferred when you call the method.
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