I'm a rookie at programming. I want to create an open list that I can add to via inputs. The if statement I created does not work. It prints the list even if I enter Y in my response to the second input. I'm sure there are many issues with this but if someone could tell me what I'm doing wrong or if there is a better alternative it would be greatly appreciated.
tickers = []
print(f'current tickers list {tickers}')
f = input("please enter a ticker symbol you would like to watch:\n")
tickers.append(f)
q = input("would you like to add another ticker symbol Y or N: ")
if q == 'Y':
print(f)
tickers.append(f)
else:
print(f'Updated tickers list {tickers}')
tickers = []
while True:
print(f'current tickers list {tickers}')
f = input("please enter a ticker symbol you would like to watch:\n")
tickers.append(f)
q = input("would you like to add another ticker symbol Y or N: ")
if q == 'Y':
pass
else:
print(f'Updated tickers list {tickers}')
break
Think about what you want your if
block to accomplish. When do you update the value of f
? You might try eg
if q == 'Y':
f = input("please enter another ticker symbol you would like to watch:\n")
tickers.append(f)
Though as a commenter remarked, you may want to keep watching more symbols -- and you might not know how many. This is an excellent opportunity to use a while
loop:
tickers = []
while True:
print(f'Current tickers list {tickers}')
f = input("Please enter a ticker symbol you would like to watch: ")
tickers.append(f)
q = input("Would you like to add another ticker symbol? (Y)es or (N)o: ")
if q.casefold() not in 'no':
break
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