Snippet of code:
def find_min(string):
a = 'b1!!Ze44B&cC3#dd$$8'
d=[]
min_=10000
for i in a:
d.append(ord(i))
for y in d:
if min_>y:
min_=y
string=chr(min_)
a=string
return a
a='b1!!Ze44B&cC3#dd$$8'
print(find_min(a))
#output=!
def delete_element(string,element):
t=''
b=find_min(a)
for i in range(len(a)):
b = find_min(a)
a=a.replace(a[i],'',i)
a = delete_element(a,b)
t= b+ t
print(a)
print(t)
print()
t=''
b=''
string=''
delete_element(a,b)
#output
'b1!Ze44B&cC3#dd$$8' ! 'b1Ze44B&cC3#dd$$8' !! 'b1Ze44B&cC3dd$$8' #!!
What should I do to finish the code? I would like the def function to return the extracted element (def min) as well as the string indicating which element was removed.
'b1!Ze44B&cC3#dd$$8'
!
'b1Ze44B&cC3#dd$$8'
!!
'b1Ze44B&cC3dd$$8'
#!!
I wanted the code output to be like this....
If I understand what you're trying to do correctly then this should work for you:
def delete_element(string):
return string.replace(sorted(string)[0], '')
print(delete_element('b1!!Ze44B&cC3#dd$$8'))
...will output b1Ze44B&cC3#dd$$8
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