How to block and wait the result of an async function in a non-async function?

Question

Very simple code:

async def callee():
    await asyncio.sleep(1)
    print ("first")
    return 1


def caller():
    callee() # how do I wait the result of this?
    print("second")


async def main():
    caller()    


if __name__ == "__main__":
    asyncio.get_event_loop().run_until_complete(main())

How do I make this work and print "first" then "second"?

Answer 1

When declaring a async function and then calling it, also requires to wait for it. Like with the await asyncio.sleep(1) , you need to await the callee() . See below:

import asyncio

async def callee():
    await asyncio.sleep(1)
    print ("first")
    return 1


async def caller():
    await callee() # how do I wait the result of this?
    print("second")


async def main():
    await caller()    


if __name__ == "__main__":
    asyncio.get_event_loop().run_until_complete(main())