How to filter an array of object inside an array of objects based on an array and also remove properties of that object?

Question

let array1= [
    { "id": 100, name: "A", "details": [{"year": "2012"},{"data": "Test1"}]},
    { "id": 101, name: "B", "details": [{"year": "2013"},{"data": "Test2"}]},
    { "id": 102, name: "C", "details": [{"year": "2014"},{"data": "Test3"}]}
];

const array2= ['2012'];

Result I wanted

{ "id": 100, name: "A", "details": [{"year": "2012"}]}

I know i can filter the array with this code

array1.filter(o => 
  o.details.some(p=> {
    return array2.includes(p.year)
  })
)

But is there a way to remove the objects as well.

Answer 1

We can reduce to avoid multiple steps

This reduce filters and deletes part of the details array

 let array1 = [ { "id": 100, name: "A", "details": [{"year": "2012"},{"data": "Test1"}]}, { "id": 101, name: "B", "details": [{"year": "2013"},{"data": "Test2"}]}, { "id": 102, name: "C", "details": [{"year": "2014"},{"data": "Test3"}]} ]; const array2 = ['2012']; let array3 = array1.reduce((acc, {id,name,details}) => { if (array2.includes(details[0].year)) { acc.push({ id, name, details: details[0] }) } return acc }, []) console.log(array3)