I have a string column which has date value in the below format
6/1/2020 12:00:00 AM
I want only the date part and convert the column to date so when i use date_trunc and parse date like below it is giving error
select CAST(DATE_TRUNC(PARSE_DATE('%m/%d/%Y', datecolumn), AS DATE)) from table name
PLease let me know what is the best way to achieve this
Use below
select date(parse_datetime('%m/%d/%Y %I:%M:%S %p', datecolumn))
from your_table
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