I'm willing to fetch all the dates that are listed in the list reducing 1 day I'm trying something like that:
select date
from MyTable
where date in ('2022-03-22', '2022-03-18', '2022-03-11') - interval 1 day
I wish to receive:
'2022-03-21', '2022-03-17', '2022-03-10'
It can be done with intervals.
Here is a link to how it works: https://www.db-fiddle.com/f/3PnzHErrf2fZFGZY67K12X/48
SELECT ADDDATE("2022-03-22", INTERVAL -1 DAY);
SELECT ADDDATE("2022-03-18", INTERVAL -1 DAY);
SELECT ADDDATE("2022-03-11", INTERVAL -1 DAY);
You can also do it with a concat for example: https://www.db-fiddle.com/f/3PnzHErrf2fZFGZY67K12X/49
SELECT CONCAT(ADDDATE("2022-03-22", INTERVAL -1 DAY),' | ',
ADDDATE("2022-03-18", INTERVAL -1 DAY),' | ',
ADDDATE("2022-03-11", INTERVAL -1 DAY));
You can add 1 day to the date
column's value to compare it against the IN
list:
SELECT date
FROM MyTable
WHERE date + INTERVAL 1 DAY IN ('2022-03-22', '2022-03-18', '2022-03-11');
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