zip(a, zip(b, c)).map { ($0, $1.0, $1.1) } Here three are being done but I need to zip four arrays.
Maybe not the prettiest, but it works:
zip(a, zip(b, zip(c, d))).map { ($0, $1.0, $1.1.0, $1.1.1) }
The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.