Hello I have a form on django that im trying to validate so it does not allow duplicated values, as of right now when you enter a duplicated value it raises this error on the app:
Exception Type: IntegrityError
Exception Value:
duplicate key violates uniqueness restriction «utiles_employee_user_id_key»
DETAIL: The key already exists (user_id)=(3).
Here's my form:
class EmployeeForm(Form):
first_name = CharField(max_length=40, label=_('Nombre'))
last_name = CharField(max_length=40, label=_('Apellido'))
children = IntegerField(label=_('Cantidad de Hijos'), required=False)
email2 = EmailField(label=_('Correo electrónico personal'), required=False)
email = EmailField(label=_('Correo electrónico Corporativo'))
company = ModelChoiceField(queryset=Company.objects.all(), required=False, label=_('Empleado de'))
def __init__(self, data=None, files=None, auto_id='id_%s', prefix=None, initial=None, error_class=ErrorList,
label_suffix=None, empty_permitted=False, user=None):
super().__init__(data, files, auto_id, prefix, initial, error_class, label_suffix, empty_permitted)
if not user.is_staff:
self.fields['company'].queryset = Company.objects.filter(id=user.employee.company.id)
how can I raise an error message saying to the user that it entered a duplicated object, as of right now the app crashes when I do.
EDIT: I added this method to the form but the problem persist.
def clean(self):
cd = self.cleaned_data['email']
user = Employee.objects.get(email2=cd)
if self.instance and not user == self.instance:
raise ValidationError('trial msg')
return cd
but now i get this error:
Exception Type: AttributeError
Exception Value:
'EmployeeForm' object has no attribute 'instance'
You can achieve the desired behavior using the clean
method. This method is present either on the Field
definition itself and also on the Form
.
You can find more detailed information on Django's documentation:
By raising a ValidationError
when the duplicate data is present, it will allow you to detect the issue in the view and then display/render the desired error message.
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