input: "20+10/5-1*2"
I want to perform arithmetic operations on that string how can I do it without using eval
method in ruby?
expected output: 20
While I hesitate to answer an interview question, and I am completely embarrassed by this code, here is one awful way to do it. I made it Ruby-only and avoided Rails helpers because it seemed more of a Ruby task and not a Rails task.
#
# Evaluate a string representation of an arithmetic formula provided only these operations are expected:
# + | Addition
# - | Subtraction
# * | Multiplication
# / | Division
#
# Also assumes only integers are given for numerics.
# Not designed to handle division by zero.
#
# Example input: '20+10/5-1*2'
# Expected output: 20.0
#
def eval_for_interview(string)
add_split = string.split('+')
subtract_split = add_split.map{ |v| v.split('-') }
divide_split = subtract_split.map do |i|
i.map{ |v| v.split('/') }
end
multiply_these = divide_split.map do |i|
i.map do |j|
j.map{ |v| v.split('*') }
end
end
divide_these = multiply_these.each do |i|
i.each do |j|
j.map! do |k, l|
if l == nil
k.to_i
else
k.to_i * l.to_i
end
end
end
end
subtract_these = divide_these.each do |i|
i.map! do |j, k|
if k == nil
j.to_i
else
j.to_f / k.to_f
end
end
end
add_these = subtract_these.map! do |i, j|
if j == nil
i.to_f
else
i.to_f - j.to_f
end
end
add_these.sum
end
Here is some example output:
eval_for_interview('1+1')
=> 2.0
eval_for_interview('1-1')
=> 0.0
eval_for_interview('1*1')
=> 1.0
eval_for_interview('1/1')
=> 1.0
eval_for_interview('1+2-3*4')
=> -9.0
eval_for_interview('1+2-3/4')
=> 2.25
eval_for_interview('1+2*3/4')
=> 2.5
eval_for_interview('1-2*3/4')
=> -0.5
eval_for_interview('20+10/5-1*2')
=> 20.0
eval_for_interview('20+10/5-1*2*4-2/6+12-1-1-1')
=> 31.0
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