How to print unicode from a generator expression in python?

Question

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Create a list from generator expression:<\/i>

V = [('\\u26' + str(x)) for x  in range(63,70)]

Answer 1

Unicode is a character to bytes encoding, not escape sequences. Python 3 strings are Unicode. To return the character that corresponds to a Unicode code point use chr :

chr(i) Return the string representing a character whose Unicode code point is the integer i. For example, chr(97) returns the string 'a', while chr(8364) returns the string '€'. This is the inverse of ord().

The valid range for the argument is from 0 through 1,114,111 (0x10FFFF in base 16). ValueError will be raised if i is outside that range.

To generate the characters between 2663 and 2670:

>>> [chr(x) for x  in range(2663,2670)]
['੧', '੨', '੩', '੪', '੫', '੬', '੭']

Escape sequences use hexadecimal notation though. 0x2663 is 9827 in decimal, and 0x2670 becomes 9840.

>>> [chr(x) for x  in range(9827,9840)]
['♣', '♤', '♥', '♦', '♧', '♨', '♩', '♪', '♫', '♬', '♭', '♮', '♯']

You can use also use hex numeric literals:

>>> [chr(x) for x  in range(0x2663,0x2670)]
['♣', '♤', '♥', '♦', '♧', '♨', '♩', '♪', '♫', '♬', '♭', '♮', '♯']

or, to use exactly the same logic as the question

>>> [chr(0x2600 + x) for x  in range(0x63,0x70)]
['♣', '♤', '♥', '♦', '♧', '♨', '♩', '♪', '♫', '♬', '♭', '♮', '♯']

The reason the original code doesn't work is that escape sequences are used to represent a single character in a string when we can't or don't want to type the character itself. The interpreter or compiler replaces them with the corresponding character immediatelly. The string \\u26 is an escaped \ followed by u , 2 and 6 :

>>> len('\\u26')
4