Below is a working example of an http request I wrote using Python requests. In said example there is a json object I convert to string using the Json Dumps function:
data = [
{"parameterName":"date",
"values":["-30d"]
},
{"parameterName":"category",
"values":["25","4","2"]
},
{"parameterName":"format",
"values":["pdf"]
},
{"parameterName":"readunread","values":["read"]}]
request = session.post(
someUrl,
headers={
'Host': someUrl,
'User-Agent': 'Mozilla/5.0 (Windows NT 10.0; Win64; x64; rv:100.0) Gecko/20100101 Firefox/100.0',
'Accept': 'application/json, text/plain, */*',
'Accept-Language': 'en-US,en;q=0.5',
'Accept-Encoding': 'gzip, deflate, br',
},
cookies=response.cookies,
data = json.dumps(data)
)
I wanted to find a unnecessarily complicated way to do this another way since Python is too straight forward and the first thing that came to mind was C# (using RestSharp):
var client = new RestSharp.RestClient();
client.BaseUrl = new Uri(someUrl);
var documents = new RestSharp.RestRequest(RestSharp.Method.POST);
documents.AddCookie("cookie",theCookies);
documents.AddHeader("Host",someHostUrl);
documents.AddHeader("User-Agent","Mozilla/5.0 (Windows NT 10.0; Win64; x64; rv:100.0) Gecko/20100101 Firefox/100.0");
documents.AddHeader("Accept","application/json, text/plain, */*");
documents.AddHeader("Accept-Language", "en-US,en;q=0.5");
documents.AddHeader("Accept-Encoding", "gzip, deflate, br");
string documentsBody = "[{\"parameterName\":\"category\",\"values\":[\"25\",\"4\",\"2\"]},{\"parameterName\":\"format\",\"values\":[\"pdf\"]},{\"parameterName\":\"date\",\"values\":[\"-30d\"]},{\"parameterName\":\"readunread\",\"values\":[\"read\"]}]";
documents.AddBody(documentsBody);
IRestResponse response = client.Execute(documents);
The Python example returns the desired response. The C# example does not. I know it is due to the formatting of the payload. What is the least obnoxious way to format the payload (as done in the Python example) but in C#?
We can try to use JsonConvert.SerializeObject
which support from Json.NET
that help us easy to serializeObject or deserialize.
We can create a class that represent to carry your parameter data as a strong type.
public class ParameterModel
{
public string parameterName { get; set; }
public List<string> values { get; set; }
}
then passing it as parameter in JsonConvert.SerializeObject
string documentsBody = Newtonsoft.Json.JsonConvert.SerializeObject(new List<ParameterModel>{
new ParameterModel(){ parameterName = "category", values = new List<string>(){"25","4","2"} },
//....
});
documents.AddBody(documentsBody);
IRestResponse response = client.Execute(documents);
EDIT
if you don't want to create a class for parameter of model, we can try to use the anonymous object .
var result = Newtonsoft.Json.JsonConvert.SerializeObject(new []{
new { parameterName = "category", values = new []{"25","4","2"} },
//....
});
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