Search for a list from a list of lists and return the results

Question

I have something like this

lists = [ [1,2,3] , [4,5,6] , [8,9,10] ]

and I would like to be able to search for a element of a list and return the entirety of the list

search = 5
result = [4,5,6] 

(doesn't have to be that exact format but I would like to be able to see all the elements from the list)

I've looked at other forums and when they search I only returns a true or false value, so I'm not sure if what I would like to do is even possible

Answer 1

You can abuse the next function to get the first element of a iterable that matches a predicate like this:

next(i for i in iterable if p(i))

If no element exists this will throw a StopIteration exception that you can optionally catch.

You can also use the in operator to find if a element is in a list:

5 in [1,2,3]
# False
5 in [4,5,6]
# True

Combining the two:

next(l for l in lists if 5 in l)

Answer 2

You can use numpy

a = np.array(lists)
out = a[np.where(a==5, True, False).any(1)].tolist()

Answer 3

In this kind of situation, I would create a function that will iterate the list and use the in operator to see if the value is in the list or not and finally return the index number of that value x or return False.

def result(srch, list):
    for x in list:
        if srch in x:
            return list[list.index(x)]
    return False


lists = [[1, 2, 3], [4, 5, 6], [8, 9, 10]]

search = 15

print(result(search, lists))

Result:

[4, 5, 6]