let array1 = ["?", "!", "."]; let array2 = ["live.", "ali!", "harp", "sharp%", "armstrong","yep?"]; console.log(array2.filter((x) => x.endsWith("?")));
The output is just: ['yep?']
Because the function endsWith()
only checked for "?"
as you see in the code. How do I loop the elements on the array1
(suffixes) inside the endsWith
function so the output is:
['live.', 'ali!', 'yep?']
You could use a regex , and then match
each element in the filter
iteration against it.
/[?!.]$/
says match one of these things in the group ( [?!.]
) before the string ends ( $
).
const arr = ['live.', 'ali!', 'harp', 'sharp%', 'armstrong', 'yep?']; const re = /[?!.]$/; const out = arr.filter(el => el.match(re)); console.log(out);
Regarding your comment you can pass in a joined array to the RegExp constructor using a template string .
const query = ['.', '?', '!']; const re = new RegExp(`[${query.join('')}]$`); const arr = ['live.', 'ali!', 'harp', 'sharp%', 'armstrong', 'yep?']; const out = arr.filter(el => el.match(re)); console.log(out);
You can use an inner .some()
call to loop over your array1
and return true
from that when you find a match instead of hardcoding the ?
:
const array1 = ["?", "!", "."]; const array2 = ["live.", "ali!", "harp", "sharp%", "armstrong","yep?"]; const res = array2.filter((x) => array1.some(punc => x.endsWith(punc))); console.log(res);
Above, when you return true
(or a truthy value) from the .some()
callback, the .some()
method will return true
, otherwise it will return false
if you never return true, thus discarding it.
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