I would like to match numbers greater than or equal to 1001(or '1001'). I tried the following pattern "^(^[1-9][0-9]{3,4}$)$"
. It matches from 1000 and above.
(?!^1000$)^[1-9]\d{3,}$
(?!^1000$)
Except the number 1000
^[1-9]\d{3,}$
Match 4 and more length numbers let regex = /(?!^1000$)^[1-9]\d{3,}$/; console.log(regex.test("1000")); console.log(regex.test("1001")); console.log(regex.test("10000")); console.log(regex.test("99995555"));
See the regex demo
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