Why does strncpy() produce garbage when the dest is smaller than the src but large enough to fit the wanted substring of src?

Question

I tried to limit the number of n bytes copied to dest (here str1 ) by using strncpy() . The dest is big enough for the n bytes, but the output produced garbage when dest is smaller than the source (here argv[1] ). This looks different, when i make dest large enough to hold the source.

Here's the code:

#include <stdio.h>                                                              
#include <string.h>                                                             
                                                                                
int main(int argc, char *argv[])                                                
{                                                                               
/* // Works when str1[?] is 20:                                                                    
  char str1[20];                                                                
  char str2[20]; */                                                             
                                                                                
  // produces garbage, str1 is smaller than argv[1] but big enough for the 4 bytes copied                                                            
  char str1[10];                                                                
  char str2[10];                                                                
                                                                                
  printf("argc = %i\n", argc);                                                  
  if (argc <= 1 || argc > 2){                                                   
    printf("Input Example:\n"                                                   
           "  %s SEGMENT:OFFSET\n"                                              
           "  %s 0100:F00A\n", argv[0], argv[0]);                               
    return 0;                                                                   
  }                                                                             
  printf("strlen(argv[1]) = %li, argv[1] = %s\n"                                
          , strlen(argv[1]), argv[1]);                                          
                                                                                
  // str1                                                                       
  strncpy(str1, argv[1], 4); // copying 4 bytes to str1                                                   
  printf("Copy only 4 Bytes -> sizeof(str1) = %li, "                            
         "strlen(str1) = %li, str1 = %s\n", sizeof(str1), strlen(str1), str1);  
                                                                                
  // str2                                                                       
  strncpy(str2, argv[1], 3); // copying 3 bytes to str2                                                   
  printf("Copy only 3 Bytes -> sizeof(str2) = %li, "                            
         "strlen(str2) = %li, str2 = %s\n", sizeof(str2), strlen(str2), str2);  
                                                                                
  return 0;                                                                     
}                      

The input of 0100:F00A produces:

./test.bin 0100:F00A
argc = 2
strlen(argv[1]) = 9, argv[1] = 0100:F00A
Copy only 4 Bytes -> sizeof(str1) = 10, strlen(str1) = 8, str1 = 0100�U
Copy only 3 Bytes -> sizeof(str2) = 10, strlen(str2) = 3, str2 = 010

Expected was just str1 = 0100 .

I also do wonder why str2 is correct, its initial array size is as small as str1 .

When i change

char str1[10] 

to

char str1[20]

and by doing so make it larger than the input of argv[1], then the output is correct:

./test.bin 0100:F00A
argc = 2
strlen(argv[1]) = 9, argv[1] = 0100:F00A
Copy only 4 Bytes -> sizeof(str1) = 20, strlen(str1) = 4, str1 = 0100
Copy only 3 Bytes -> sizeof(str2) = 20, strlen(str2) = 3, str2 = 010

It seems like strncpy is first copying everything to dest and then cutting away the rest after it. But is that the way how strncpy works? I assumed it is only copying what is need, the 4 bytes.

Answer 1

from man page https://linux.die.net/man/3/strncpy

The strncpy() function is similar, except that at most n bytes of src are copied. Warning: If there is no null byte among the first n bytes of src, the string placed in dest will not be null-terminated.

ie in your case not null is placed in dest

Answer 2

From the GLIBC manual page for strncpy() :

Warning : If there is no null byte among the first n bytes of src , the string placed in dest will not be null-terminated.

You are observing the effect.

Answer 3

For whatever it's worth, I tried compiling and running your program as-is on my PC (Windows/GCC 10.3.0) ... and, superficially, it "looked OK". I did NOT see the artifacts you described.

This example illustrates what's happening:

#include <stdio.h>                                                              
#include <string.h>                                                             
                                                                                
int main(int argc, char *argv[])                                                
{ 
  char *s;
  char test1[] = "AAAAAAAA";                                                                             
  char test2[] = "AAAAAAAA";                                                                             

  printf("BEFORE: strlen(test1)=%lli, sizeof(test1)=%lli, test1=%s...\n",
    strlen(test1), sizeof(test1), test1);

  strncpy(test1, "BBBB", 4);
  printf("AFTER: strlen(test1)=%lli, sizeof(test1)=%lli, test1=%s...\n",
    strlen(test1), sizeof(test1), test1);

  strncpy(test2, "BBBB", 6);
  printf("AFTER: strlen(test2)=%lli, sizeof(test2)=%lli, test2=%s...\n",
    strlen(test2), sizeof(test2), test2);

  return 0;
}

  - gcc -o x -g -Wall -pedantic x.c
x.c:37:3: warning: 'strncpy' output truncated before terminating nul copying 4 bytes from a string of the same length [-Wstringop-truncation]
   37 |   strncpy(test1, "BBBB", 4);
      |   ^~~~~~~~~~~~~~~~~~~~~~~~~

  - x 0100:F00A
segment=0100, strlen(segment)=4; offset=F00A, strlen(offset)=4
BEFORE: strlen(test1)=8, sizeof(test1)=9, test1=AAAAAAAA...
AFTER: strlen(test1)=8, sizeof(test1)=9, test1=BBBBAAAA...
AFTER: strlen(test2)=4, sizeof(test2)=9, test2=BBBB...

ADDITIONAL NOTES:

• Some systems (the BSDs, Solaris, and others) provide strlcpy() .

  It copies at most size-1 bytes to dest, always adds a terminating null byte, and does not pad the target with (further) null bytes.

• Another way to parse your command line into "segment" and offset" might be to use strtok() :

   ... if (argc != 2) { printf("USAGE: enter SEGMENT:OFFSET, eg \"0100:F00A\"\n"); return 1; } if ((strlen(argv[1]) != 9) || (strchr(argv[1], ':') == NULL)) { printf ("This doesn't look like a segment::offset!\n"); return 1; } s = strtok(argv[1], ":"); if (s == NULL){ printf("Illegal entry: unable to parse %s\n", argv[1]); } else { strcpy(segment, s); strcpy (offset, strtok(NULL, ":")); printf("segment=%s, strlen(segment)=%lli; offset=%s, strlen(offset)=%lli\n", segment, strlen(segment), offset, strlen(offset)); }