JS Regex to match a start and end pattern plus contain square brackets

Question

Sample input string

"Hi ${spurs.stadium[capacity]}" to return "${spurs.stadium[capacity]}"
"Hi ${spurs.stadium}" to return ""
"Hi ${spurs.stadium{capacity}}" to return ""

So I am looking for pattern where

1. string starts with "${spurs."
2. string must contain after this square brackets which can have any content
3. end with "}"

I have tried const regex = /[$]{spurs.+?[}]/gi but it doesn't require the square brackets it seems optional. Any ideas?

Answer 1

You want to match by order of appearance. Left to right.

EDIT: added a lazy (not greedy) quantifier ?

 var str = "Hi ${spurs.stadium[capacity]} dog" // to return "${spurs.stadium[capacity]}" var str2 = "Hi ${spurs.stadium}" // to return "" var str3 = "Hi ${spurs.stadium{capacity}}" // to return "" var str4 = "Hi ${spurs.stadium[capacity]} ${spurs.stadium[crowd]}"; const regex = /\${spurs\..*?\[.*?\]}/gi console.log(str.match(regex)); console.log(str2.match(regex)); console.log(str3.match(regex)); console.log(str4.match(regex));

Answer 2

Use the following:

\${spurs.*\[(.*)\]\}

1. \$ - literal dollar

2. spurs.*\[ - spurs and any character after until opening square bracket

3. (.*)\] - any character until closing square bracket (saved in a capture group for extraction later, if needed

4. \} - closing bracket

Here is a working example :

Answer 3

Try this solution which uses the match() method(more info on it here ):

const paragraph = '"Hi ${spurs.stadium[capacity]}" to return "${spurs.stadium[capacity]}" "Hi ${spurs.stadium}" to return "" "Hi ${spurs.stadium{capacity}}" to return ""';

const regex = /{.*?}/g;

const found = paragraph.match(regex);

console.log(found);