os.rename(source, destination) The filename, directory name, or volume label syntax is incorrect

Question

import os

f = open("Names.txt", "r") 
names = f.readlines()

folder = r'C:\Users\e007l\Desktop\Rename\\'

count = 1

for file_name in os.listdir(folder):
    source = folder + file_name
    destination = folder + names[int(count)] + ".txt"
    os.rename(source, destination)
    count += 1
    res = os.listdir(folder)

print(res)
print(folder)

This is should change the names of the files in the folder to the names in my list but it won't it simply gives me the error message:

[WinError 123] The filename, directory name, or volume label syntax is incorrect: 'C:\Path\\names1.txt' -> 'C:\Path\\Beta\n.txt'

My text file Names.txt has this inside:

Alpha Beta Delta Omega

Those are the names I want to Give to the existing files

Answer 1

1. Use the print() function to check the path of the destination folder.
2. Use os.path.join() to construct your destination path, which would save you a lot of trouble of having to decide whatever kind of slashes to use, you probably had an error in how you decided your destination path.