spring boot jdbcTemplate.query throws table not found auto converting table name to upper case

Question

i have a jdbcTemplate.query method with query bit complex with multiple left joins, so its difficult for me to implement interface based repository methods.

I am using a MySQL db from AWS RDS.

when the query is executing spring boot jpa automatically converting table name to upper case and it throws error as: table not found.

exception is:

with path [] threw exception [Request processing failed; nested exception is org.springframework.jdbc.BadSqlGrammarException: StatementCallback; bad SQL grammar [SELECT DISTINCT test_desc FROM test_name_table ]; nested exception is org.h2.jdbc.JdbcSQLSyntaxErrorException: Table "TEST_NAME_TABLE" not found; SQL statement: SELECT DISTINCT test_desc FROM test_name_table [42102-200]] with root cause org.h2.jdbc.JdbcSQLSyntaxErrorException: Table "TEST_NAME_TABLE" not found; SQL statement: SELECT DISTINCT test_desc FROM test_name_table [42102-200]

here are the solutions i have tried:

from application.properties:

spring.jpa.hibernate.naming.physical-strategy=org.hibernate.boot.model.naming.PhysicalNamingStrategyStandardImpl spring.jpa.database-platform=org.hibernate.dialect.MySQL8Dialect spring.jpa.hibernate.naming_strategy = org.hibernate.cfg.DefaultNamingStrategy

database url:

spring.datasource.dataSourceProperties.serverName=test-instance.us-east-1.rds.amazonaws.com;DATABASE_TO_UPPER=FALSE;CASE_INSENSITIVE_IDENTIFIERS=TRUE;

as you see above sql query, i have even put the table name inside backtick. but no luck.

I tried to rename the table name in MySQL to TEST_NAME_TABLE, but still no luck.

any recommended fix for this?

Answer 1

its a good practice use @Table(name = "table_name") for a model and @Column(name = "column_name") annotation for every column in your Model.java

and use @Query("some query in SQL") for every query you use in ModelRepository.java

example:

@Entity
@Table
public class Employee implements Serializable {
    @Id

    @Column(name = "emp_id")
    private Long id;

    @Column(name = "name")
    private String name;

    @Column(name = "email")
    private String email;

    @Column(name = "jobTitle")
    private String jobTitle;

    @Column(name = "phone")
    private String phone;

    @Column(name = "imagUrl")
    private String imageUrl;

    @Column(name = "employeeCode")
    private String employeeCode;
}

@Repository
public interface EmployeeRepository extends JpaRepository<Employee, Long> {

    @Query("SELECT s FROM Employee s WHERE s.email = ?1")
    Optional<Employee> findEmployeeByEmail(String email);
}