Scheme (Racket) how to return a string in a list without quotation

Question

I'm trying to return a list of strings.

I am using (list “stringA” “stringB”)

And it is returning “string A” “stringB”

Is there anyway it can return stringA stringB ?

Answer 1

There are different ways of making a list. Some basic lists are:

(f x y)     ; run function f, substitute values x and y
(list x y)  ; create list, substitute values x and y
'(x y)      ; create list, don't substitute x and y

(quote x y) ; Common Lisp alternative of '(x y)

If you go for (list stringA stringB) then Scheme will try to replace stringA stringB with their values.

What you want is '(stringA stringB)