I spent hours trying to figure this out. I have four binary values that I want to combine into a single number. I got it working with two numbers but I need to get it working with four.
int Index = ((Bitplane0_ROW[p] & (1 << N)) >> N) | (((Bitplane1_ROW[p] & (1 << N)) >> N) << 1); // Works
I am stumped. Thanks in advance.
Edit.. Here is the complete program.
int main()
{
int Bitplane0_ROW[] = { 0b01100110 , 0b11111111, 0b01011010, 0b01111110, 0b00000000, 0b10000001, 0b11111111, 0b01111110 }; // Array to to store numbers Last Row is first.
int Bitplane1_ROW[] = { 0b01111110, 0b11111111, 0b11111111, 0b11011011, 0b11111111, 0b01111110, 0b00000000, 0b00000000 };
int Bitplane2_ROW[] = { 0b00000000, 0b00000000,0b00000000,0b00000000,0b00000000,0b00000000,0b00000000,0b00000000};
int Bitplane3_ROW[] = { 0b00000000, 0b00000000,0b00000000,0b00000000,0b00000000,0b00000000,0b00000000,0b00000000 };
int N = 7; //to store bit
int c = 0;
BYTE* buf = new BYTE[8 * 5];
unsigned char White[] = {255, 255, 255};
unsigned char Green[] = {53, 189,104 };
unsigned char Brown[] = {59,85,142 };
unsigned char Tan[] = {154,194,237 };
for (int p = 0; p < 8; p++)
{
for (int j = 0; j < 8; j++) // Row 6
{
int Index = ((Bitplane0_ROW[p] & (1 << N)) >> N) | (((Bitplane1_ROW[p] & (1 << N)) >> N) << 1); // Works
if(Index == 0)
{
// Index 0 (White)
// Index = 0;
buf[c + 0] = White[Index];
buf[c + 1] = White[Index+1];
buf[c + 2] = White[Index+2];
}
else if (Index == 1)
{
// Index 1 (Green)
//Index = 0;
buf[c + 0] = Green[Index];
buf[c + 1] = Green[Index+1];
buf[c + 2] = Green[Index+2];
}
else if (Index == 2)
{
// Index 2 (Brown)
//Index = 0;
buf[c + 0] = Brown[Index];
buf[c + 1] = Brown[Index+1];
buf[c + 2] = Brown[Index+2];
}
else if (Index == 3)
{
// Index 3 (Tan)
Index = 0;
buf[c + 0] = Tan[Index];
buf[c + 1] = Tan[Index+1];
buf[c + 2] = Tan[Index+2];
}
else if (Index == 15)
{
// Index 1 (Green)
Index = 0;
buf[c + 0] = Green[Index];
buf[c + 1] = Green[Index+1];
buf[c + 2] = Green[Index+2];
}
c += 3;
N--;
}
N = 7;
}
SaveBitmapToFile((BYTE*)buf, 8, 8, 24, 0, "C:\\Users\\Chris\\Desktop\\Link_Sprite.bmp");
delete[] buf;
return 0;
You can shift the bits manually or just use std::bitset
:
#include <bitset>
// ...
std::bitset<4> bs;
bs.set(0, (Bitplane0_ROW[p] >> N) & 1);
bs.set(1, (Bitplane1_ROW[p] >> N) & 1);
bs.set(2, (Bitplane2_ROW[p] >> N) & 1);
bs.set(3, (Bitplane3_ROW[p] >> N) & 1);
unsigned long index = bs.to_ulong();
Here's a more complete revision, note I commented out your saveBitMapFil and change the BYTE type because I don't know how to have them in my revision.
the key bit of code is this snippet, with a debug statement
N = 1;
for (int j = 7; j >=0; j--) // I reversed you loop
{
N = 1<<j;
Index = ((Bitplane0_ROW[p] & N ? 1 :0)<<3)
+ ((Bitplane1_ROW[p] & N ? 1 :0)<<2)
+ ((Bitplane2_ROW[p] & N ? 1 :0)<<1)
+ (Bitplane3_ROW[p] & N ? 1 :0);
std::cout << " Index = " << std::bitset<4>(Index) << std::endl;
#include <iostream>
#include <bitset>
using namespace std;
int main()
{
int Bitplane0_ROW[] = { 0b01100110 , 0b11111111, 0b01011010, 0b01111110, 0b00000000, 0b10000001, 0b11111111, 0b01111110 }; // Array to to store numbers Last Row is first.
int Bitplane1_ROW[] = { 0b01111110, 0b11111111, 0b11111111, 0b11011011, 0b11111111, 0b01111110, 0b00000000, 0b00000000 };
int Bitplane2_ROW[] = { 0b00000000, 0b00000000,0b00000000,0b00000000,0b00000000,0b00000000,0b00000000,0b00000000};
int Bitplane3_ROW[] = { 0b00000000, 0b00000000,0b00000000,0b00000000,0b00000000,0b00000000,0b00000000,0b00000000 };
int N = 7; //to store bit
int c = 0;
unsigned char* buf = new unsigned char[8 * 5];
unsigned char White[] = {255, 255, 255};
unsigned char Green[] = {53, 189,104 };
unsigned char Brown[] = {59,85,142 };
unsigned char Tan[] = {154,194,237 };
int Index = 0;
for (int p = 0; p < 8; p++)
{
N = 1;
for (int j = 7; j >=0; j--) // I reversed you loop
{
N = 1<<j;
Index = ((Bitplane0_ROW[p] & N ? 1 :0)<<3)
+ ((Bitplane1_ROW[p] & N ? 1 :0)<<2)
+ ((Bitplane2_ROW[p] & N ? 1 :0)<<1)
+ (Bitplane3_ROW[p] & N ? 1 :0);
std::cout << " Index = " << std::bitset<4>(Index) << std::endl;
//int Index = ((Bitplane0_ROW[p] & (1 << N)) >> N) | (((Bitplane1_ROW[p] & (1 << N)) >> N) << 1); // Works
if(Index == 0)
{
// Index 0 (White)
// Index = 0;
buf[c + 0] = White[Index];
buf[c + 1] = White[Index+1];
buf[c + 2] = White[Index+2];
}
else if (Index == 1)
{
// Index 1 (Green)
//Index = 0;
buf[c + 0] = Green[Index];
buf[c + 1] = Green[Index+1];
buf[c + 2] = Green[Index+2];
}
else if (Index == 2)
{
// Index 2 (Brown)
//Index = 0;
buf[c + 0] = Brown[Index];
buf[c + 1] = Brown[Index+1];
buf[c + 2] = Brown[Index+2];
}
else if (Index == 3)
{
// Index 3 (Tan)
Index = 0;
buf[c + 0] = Tan[Index];
buf[c + 1] = Tan[Index+1];
buf[c + 2] = Tan[Index+2];
}
else if (Index == 15)
{
// Index 1 (Green)
Index = 0;
buf[c + 0] = Green[Index];
buf[c + 1] = Green[Index+1];
buf[c + 2] = Green[Index+2];
}
c += 3;
N--;
}
N = 7;
}
// SaveBitmapToFile((BYTE*)buf, 8, 8, 24, 0, "C:\\Users\\Chris\\Desktop\\Link_Sprite.bmp");
delete[] buf;
}
your code contained the first char
int Bitplane0_ROW[] = { 0b01100110
int Bitplane1_ROW[] = { 0b01111110
int Bitplane2_ROW[] = { 0b00000000
int Bitplane3_ROW[] = { 0b00000000
and the debug produces the same data pivoted
Index = 0000
Index = 1100
Index = 1100
Index = 0100
Index = 0100
Index = 1100
Index = 1100
Index = 0000
Just n = 8 b3 + 4 b2 + 2 b1 + b0
.
The retrieval of the bits can be done with
(n >> 3) & 1
(n >> 2) & 1
(n >> 1) & 1
n & 1
The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.