I have a data frame
cat input.csv
dwelling,wall,weather,occ,height,temp
5,2,Ldn,Pen,154.7,23.4
5,4,Ldn,Pen,172.4,28.7
3,4,Ldn,Pen,183.5,21.2
3,4,Ldn,Pen,190.2,30.3
To which I'm trying to apply the following function:
input_df = pd.read_csv('input.csv')
def folder_column(row):
if row['dwelling'] == 5 and row['wall'] == 2:
return 'folder1'
elif row['dwelling'] == 3 and row['wall'] == 4:
return 'folder2'
else:
return 0
I want to run the function on the input dataset and store the output in a separate data frame using something like this:
temp_df = pd.DataFrame()
temp_df = input_df['archetype_folder'] = input_df.apply(folder_column, axis=1)
But when I do this I only get the newly created 'archetype_folder' in the temp_df, when I would like all the original columns from the input_df. Can anyone help? Note that I don't want to add the new column 'archetype_folder' to the original, input_df. I've also tried this:
temp_df = input_df
temp_df['archetype_folder'] = temp_df.apply(folder_column, axis=1)
But when I run the second command both input_df and temp_df end up with the new column?
Any help is appreciated!
You need to create copy of original DataFrame, then assign return values of your function to it, consider following simple example
import pandas as pd
def is_odd(row):
return row.value % 2 == 1
df1 = pd.DataFrame({"value":[1,2,3],"name":["uno","dos","tres"]})
df2 = df1.copy()
df2["odd"] = df1.apply(is_odd,axis=1)
print(df1)
print("=====")
print(df2)
gives output
value name
0 1 uno
1 2 dos
2 3 tres
=====
value name odd
0 1 uno True
1 2 dos False
2 3 tres True
Use Dataframe.copy :
temp_df = input_df.copy()
temp_df['archetype_folder'] = temp_df.apply(folder_column, axis=1)
You don't need apply
. Use .loc
to be more efficient.
temp_df = input_df.copy()
m1 = (input_df['dwelling'] == 5) & (input_df['wall'] == 2)
m2 = (input_df['dwelling'] == 3) & (input_df['wall'] == 4)
temp_df.loc[m1, 'archetype_folder'] = 'folder1'
temp_df.loc[m2, 'archetype_folder'] = 'folder2'
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