Get Date in specified format in python

Question

I am looking to get today's date and n - today's date in the format below: -

tod = datetime.datetime.now()
d = datetime.timedelta(days = 365)
x = tod - d

I want x and tod in YYYYMMDD format for eg: 20230130 How do I get it to this format

Answer 1

the datetime class has an strftime function that allows you to convert a datetime to string in the format you set (more info here: https://docs.python.org/3/library/datetime.html#strftime-and-strptime-format-codes ).

import datetime
tod = datetime.datetime.now()
d = datetime.timedelta(days = 365)
x = tod - d
print(x.strftime("%Y%m%d"))

output:

20230130

Answer 2

import datetime
tod = datetime.datetime.now()
d = datetime.timedelta(days = 365)
x = tod - d

#Before formatting
#print(d) #365 days, 0:00:00
#print(x) #2022-01-30 05:59:48.328091

#strftime can be used to format as your choice %Y for year, %m for month, %d for date

tod_ = tod.strftime("%Y%m%d")
x_ = x.strftime("%Y%m%d")

print(tod_) #20230130
print(x_)   #20220130

Answer 3

A similar answer is here Convert datetime object to a String of date only in Python . It use datetime.datetime.strftime method to work. For example in your case:

import datetime
tod = datetime.datetime.now()
d = datetime.timedelta(days = 365)
x = tod - d
print(x.strftime('%Y%m%d'))