I want to sort a personArray
with age
and name
:
final personArray = [
_Person(age: 10, name: 'Dean'),
_Person(age: 20, name: 'Jack'),
_Person(age: 30, name: 'Ben'),
_Person(age: 30, name: 'Alice'),
];
personArray.sort((p1, p2) {
return Comparable.compare(p1.age, p2.age);
});
for (final element in personArray) {
print(element.name);
}
Console print: Dean Jack Ben Alice.
But what I want is: Dean Jack Alice Ben.
The pseudocode looks like:
personArray.sort((p1, p2) {
return Comparable.compare(p1.age, p2.age) && Comparable.compare(p1.name, p2.name);
});
Anyway can do it?
Change your compare function
personArray.sort((p1, p2) {
final compare = Comparable.compare(p1.age, p2.age);
return compare == 0 ? Comparable.compare(p1.name, p2.name) : compare;
});
you can try this code
personArray.sort((a, b) {
return a.name.compareTo(b.name);
});
it will sort the objects with respect to name.
personArray.sort((a, b) {
if (a.age != b.age) {
return a.age - b.age;
} else {
return a.name.compareTo(b.name);
}
});
and this will sort it first with age and if both the age are equal then it will sort the objects with respect to name.
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