How to open app for "tel:111111111" link in android webview
Question
I have problem to open direct contact link in android webview Error: "
Webpage not available
The webpage at 8806288365 could not be loaded because:
net::ERR_UNKNOWN_URL_SCHEME" Please help.. Thnaks
If any link like, whatsapp: open in android webview, then I want to open dialer and whatsapp like this
My Code:
class WebViewClientDemo extends WebViewClient {
@Override
//Keep webview in app when clicking links
public boolean shouldOverrideUrlLoading(WebView view, String url) {
// view.loadUrl(url);
// return true;
if (url.startsWith("tel:")) {
// Handle telephone URLs
Intent intent = new Intent(Intent.ACTION_DIAL);
intent.setData(Uri.parse(url));
view.getContext().startActivity(intent);
return true;
} else if (url.startsWith("mailto:")) {
// Handle email URLs
Intent intent = new Intent(Intent.ACTION_SENDTO);
intent.setData(Uri.parse(url));
view.getContext().startActivity(intent);
return true;
} else {
// Load all other URLs within the WebView
view.loadUrl(url);
return true;
}
}
}
1 answers
solution1
0 2023-06-01 19:21:03
To handle the "tel:" link in an Android WebView, you need to override the WebView's URL loading behavior and intercept the "tel:" URL scheme to open the phone dialer.
Create a Custom WebViewClient and implement as below-
val webView = findViewById<WebView>(R.id.webView)
webView.webViewClient = CustomWebViewClient()
val htmlContent = "<html><a href=\"tel:8806288365\" >phone</a></html>"
webView.loadDataWithBaseURL(null, htmlContent, "text/html", "UTF-8", null)
class CustomWebViewClient : WebViewClient() {
override fun shouldOverrideUrlLoading(view: WebView?, request: WebResourceRequest?): Boolean {
// return super.shouldOverrideUrlLoading(view, request)
val url = request?.url?.toString()
if (url?.startsWith("tel:") == true) {
val intent = Intent(Intent.ACTION_DIAL)
intent.data = Uri.parse(url)
view?.context?.startActivity(intent)
return true
}
return false
}
}
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