i want to execute a sql at php which does something like changing a text column into int column.
however, this sql failed to fun at php and succeeds in my mysql admin tool (sqlyog). server responses "1 row(s) affected. 1 warning(s)". but "SHOW WARNINGS" didn't pop up anything and not surprisingly, php's mysql_error() didn't return anything.
thanks.
The best is to use the mysqli extension instead of the old mysql extension, as mysqli supports all of MySQL's features and offers the mysqli_get_Warnings() function. Without mysqli you can do mysql_query("SHOW WARNINGS");
(see SHOW WARNINGS docs) and then read the warnings from the result set.
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