In Google App Engines, how to display the HTML source of a page of a fetched URL in Python?

Question

On Google App Engine I found this code that is fetching a web page's URL:

from google.appengine.api import urlfetch
url = "http://www.google.com/"
result = urlfetch.fetch(url)
if result.status_code == 200:
  doSomethingWithResult(result.content)

Is this the right code to fecth that page's HTML source? Does the result variable contain HTML sorce of http://www.google.com/ ? If yes, what Python command I should use here instead of doSomethingWithResult(result.content) in order to display that HTML source? print result doesn't seem to be the right way.

Answer 1

Yes, result.content will contain the raw content of that page. You should check the Content-Type header and verify that it's either text/html or application/xhtml+xml .

To write the content of that page to the response, first write your status and headers and then:

self.response.out.write(result.content)