I am trying to make an HTTP request in Python 2.6.4, using the urllib module. Is there any way to set the request headers?
I am sure that this is possible using urllib2, but I would prefer to use urllib since it seems simpler.
There isn't any way to do that, which is precisely the reason urllib
is deprecated in favour of urllib2
. So just use urllib2
rather than writing new code to a deprecated interface.
I don't think so, but urllib2 can. Check out the documentation of urllib2.Request .
You could actually overwrite methods in FancyURLopener
, but that does not seem right (see http://docs.python.org/library/urllib.html#urllib._urlopener ). You could also use httplib
which basically is the backend for urllib
.
But anyhow, using urllib2
might be the best idea. It is not difficult to use. (I use it all the time.)
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