I had
exec(
"curl".
" --cert $this->_cCertifikatZPKomunikace".
" --cacert $this->_cCertifikatPortalCA".
" --data \"request=".urlencode($fc_xml)."\"".
" --output $lc_filename_stdout".
" $this->_cPortalURL".
" 2>$lc_filename_stderr",
$la_dummy,$ln_RetCode
);
in php.
I have to do it via java. Can you help me?
Thanks Jakub
I use the HttpClient methods:
import org.apache.commons.httpclient.HttpClient;
import org.apache.commons.httpclient.HttpException;
import org.apache.commons.httpclient.HttpMethod;
import org.apache.commons.httpclient.methods.GetMethod;
like so:
HttpClient client = new HttpClient();
HttpMethod method = new GetMethod("http://www.google.com");
int responseCode = client.executeMethod(method);
if (responseCode != 200) {
throw new HttpException("HttpMethod Returned Status Code: " + responseCode + " when attempting: " + url);
}
String rtn = StringEscapeUtils.unescapeHtml(method.getResponseBodyAsString());
EDIT: Oops. StringEscapeUtils comes from commons-lang. http://commons.apache.org/lang/api/org/apache/commons/lang/StringEscapeUtils.html
Take a look at URLConnection . Sun has some examples . It has various subclasses that support some specific HTTP and HTTPS features.
in addition to the pure Java answers by Quotidian and Yacoby you can try to execute the curl binary as in php. Check out how to use the ProcessBuilder
class.
cURL站点链接到Github上的Java Bindings 。
You can use HtmlUnit API in Java
import com.gargoylesoftware.htmlunit.WebClient;
import com.gargoylesoftware.htmlunit.html.HtmlPage;
like so:
WebClient webClient = new WebClient();
HtmlPage homePage = webClient.getPage("http://www.google.com");
String homePageString = homePage.asXml();
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