I want to do something like this:
class SomeClass<T>
{
SomeClass()
{
bool IsInterface = T is ISomeInterface;
}
}
What is the best way for something like this?
Note: I am not looking to constrain T
with a where
, but I would like my code to be aware of what types of interfaces T
implements. I would prefer that I don't have to construct a T
.
I don't think you can use the is
operator for this. But you can use IsAssignableFrom:
bool IsInterface = typeof(ISomeInterface).IsAssignableFrom(typeof(T));
should use following instead
bool IsInterface = typeof(ISomeInterface).IsAssignableFrom(typeof(T));
is operator
is
operator is used to check whether the run-time type
of an object is compatible
with a given type
.
An expression where the use of is
conforms to the syntax, evaluates to true, if both of the following conditions are met:
References
You can use IsAssignableFrom :
class SomeClass<T>
{
SomeClass()
{
bool IsIComparable = typeof(IComparable).IsAssignableFrom(typeof(T));
}
}
bool IsInterface = typeof(ISomeInterface).IsAssignableFrom(typeof(T))
我相信你能做到最好:
bool IsInterface = typeof(ISomeInterface).IsAssignableFrom(typeof(T));
You could try doing something like
Type Ttype = typeof(T);
That will give you the full power of the Type class, which has functions like "FindInterfaces".
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