What does this macro define?

Question

I read this piece of macro(C code) and was confused in decoding it to know what it defines. What does it define?

#define sram (*((unsigned char (*)[1]) 0))

-AD

Answer 1

I think sram means "start of RAM".

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unsigned char[1]

An array of size 1 of unsigned chars.

unsigned char(*)[1]

A pointer to an array of size 1 of unsigned chars.

(unsigned char (*)[1]) 0

Cast 0 to a pointer to an array of size 1 of unsigned chars.

*((unsigned char (*)[1]) 0)

Read some memory at location 0, and interpret the result as an array of size 1 of unsigned chars.

(*((unsigned char (*)[1]) 0))

Just to avoid 1+5*8+1==42 .

#define sram (*((unsigned char (*)[1]) 0))

Define the variable sram to the memory starting at location 0, and interpret the result as an array of size 1 of unsigned chars.

Answer 2

我认为它返回内存（RAM）的基地址（0）:)

Answer 3

It defines "sram" as a pointer to memory starting at zero. You can access memory via the pointer, eg sram[0] is address zero, sram[1] is the stuff at address one, etc.

Specifically it is casting 0 to be a pointer to an array of unsigned char and going indirect through that (leaving an array of unsigned char).

A similar result can be obtained by

#define sram ((unsigned char*)0)

It is also completely undefined in standard C, but that doesn't stop people from using it and having angels fly out of their navels.