will we have to replace every $ with jquery?
$(document).ready(function() {
$('.tabs a').click(function(){
switch_tabs($(this));
});
switch_tabs($('.defaulttab'));
});
function switch_tabs(obj)
{
$('.tab-content').hide();
$('.tabs a').removeClass("selected");
var id = obj.attr("rel");
$('#'+id).show();
obj.addClass("selected");
}
As long as you are sure the snippet contains just jQuery usage of $ then you can wrap it in a closure
(function($){
$(document).ready(function() {
$('.tabs a').click(function(){
switch_tabs($(this));
});
switch_tabs($('.defaulttab'));
});
function switch_tabs(obj)
{
$('.tab-content').hide();
$('.tabs a').removeClass("selected");
var id = obj.attr("rel");
$('#'+id).show();
obj.addClass("selected");
}
})(jQuery);
use
$.noConflict();
(function($) {
$(function() {
// more code using $ as alias to jQuery
});
})(jQuery);
// other code using $ as an alias to the other library
Resolve the conflict issues
More detail : http://api.jquery.com/jQuery.noConflict/
var $j = jQuery.noConflict();
$j(document).ready(function() {
$j('.tabs a').click(function(){
switch_tabs($j(this));
});
switch_tabs($j('.defaulttab'));
});
function switch_tabs(obj)
{
$j('.tab-content').hide();
$j('.tabs a').removeClass("selected");
var id = obj.attr("rel");
$j('#'+id).show();
obj.addClass("selected");
}
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