MySQL DISTINCT on a GROUP_CONCAT()

Question

I am doing SELECT GROUP_CONCAT(categories SEPARATOR ' ') FROM table . Sample data below:

categories
----------
test1 test2 test3
test4
test1 test3
test1 test3

However, I am getting test1 test2 test3 test4 test1 test3 back and I would like to get test1 test2 test3 test4 back. Any ideas?

Many thanks!

Answer 1

GROUP_CONCAT具有DISTINCT属性：

SELECT GROUP_CONCAT(DISTINCT categories ORDER BY categories ASC SEPARATOR ' ') FROM table

Answer 2

Using DISTINCT will work

SELECT GROUP_CONCAT(DISTINCT(categories) SEPARATOR ' ') FROM table

REf:- this

Answer 3

Other answers to this question do not return what the OP needs, they will return a string like:

test1 test2 test3 test1 test3 test4

(notice that test1 and test3 are duplicated) while the OP wants to return this string:

test1 test2 test3 test4

the problem here is that the string "test1 test3" is duplicated and is inserted only once, but all of the others are distinct to each other ( "test1 test2 test3" is distinct than "test1 test3" , even if some tests contained in the whole string are duplicated).

What we need to do here is to split each string into different rows, and we first need to create a numbers table:

CREATE TABLE numbers (n INT);
INSERT INTO numbers VALUES
(1),(2),(3),(4),(5),(6),(7),(8),(9),(10);

then we can run this query:

SELECT
  SUBSTRING_INDEX(
    SUBSTRING_INDEX(tableName.categories, ' ', numbers.n),
    ' ',
    -1) category
FROM
  numbers INNER JOIN tableName
  ON
    LENGTH(tableName.categories)>=
    LENGTH(REPLACE(tableName.categories, ' ', ''))+numbers.n-1;

and we get a result like this:

test1
test4
test1
test1
test2
test3
test3
test3

and then we can apply GROUP_CONCAT aggregate function, using DISTINCT clause:

SELECT
  GROUP_CONCAT(DISTINCT category ORDER BY category SEPARATOR ' ')
FROM (
  SELECT
    SUBSTRING_INDEX(SUBSTRING_INDEX(tableName.categories, ' ', numbers.n), ' ', -1) category
  FROM
    numbers INNER JOIN tableName
    ON LENGTH(tableName.categories)>=LENGTH(REPLACE(tableName.categories, ' ', ''))+numbers.n-1
  ) s;

Please see fiddle here .

Answer 4

SELECT
  GROUP_CONCAT(DISTINCT (category))
FROM (
  SELECT
    SUBSTRING_INDEX(SUBSTRING_INDEX(tableName.categories, ' ', numbers.n), ' ', -1) category
  FROM
    numbers INNER JOIN tableName
    ON LENGTH(tableName.categories)>=LENGTH(REPLACE(tableName.categories, ' ', ''))+numbers.n-1
  ) s;   

This will return distinct values like: test1,test2,test4,test3

Answer 5

DISTINCT ：将为您提供独特的价值。

SELECT GROUP_CONCAT(DISTINCT(categories )) AS categories FROM table

Answer 6

You can simply add DISTINCT in front.

SELECT GROUP_CONCAT(DISTINCT categories SEPARATOR ' ')

if you want to sort,

SELECT GROUP_CONCAT(DISTINCT categories ORDER BY categories ASC SEPARATOR ' ')

Answer 7

select group_concat(distinct(tablename.column1)) as column1 from tablename