std::map::const_iterator template compilation error

Question

I have a template class that contains a std::map that stores pointers to T which refuses to compile:

template <class T>
class Foo
{
public:
  // The following line won't compile
  std::map<int, T*>::const_iterator begin() const { return items.begin(); }

private:
  std::map<int, T*> items;
};

gcc gives me the following error:

error: type 'std::map<int, T*, std::less<int>, std::allocator<std::pair<const int, T*> > >' is not derived from type 'Foo<T>'

Similarly, the following also refuses to compile:

typedef std::map<int, T*>::const_iterator ItemIterator;

However, using a map that doesn't contain the template type works OK, eg:

template <class T>
class Foo
{
public:
  // This is OK
  std::map<int, std::string>::const_iterator begin() const { return items.begin(); }

private:
  std::map<int, std::string> items;
};

I assume this is related to templates and begs the question - how can I return a const_iterator to my map?

Answer 1

Use typename :

typename std::map<int, T*>::const_iterator begin() const ...

When this is first passed by the compiler, it doesn't know what T is. Thus, it also doesn't know wether const_iterator is actually a type or not.

Such dependent names (dependent on a template parameter) are assumed to

• not be types unless prefixed by typename
• not to be templates unless directly prefixed by template .

Answer 2

您需要输入typename ：

typename std::map<int, T*>::const_iterator begin() const { return items.begin(); }

Answer 3

You need:

typename std::map<int, T*>::const_iterator begin() const { return items.begin(); }

Or simpler

typedef typename std::map<int, T*>::const_iterator const_iterator;
const_iterator begin() const { return items.begin(); }

This is because const_iterator is dependent name on T so you need to tell compiler that it is actually type.