How can I return an anonymous type from a method?

Question

I have a Linq query that I want to call from multiple places:

var myData = from a in db.MyTable
             where a.MyValue == "A"
             select new  {
                            a.Key,
                            a.MyValue
                          };

How can I create a method, put this code in it, and then call it?

public  ???  GetSomeData()
{
   // my Linq query
}

Answer 1

IQueryable and IEnumerable both work. But you want to use a type specific version, IQueryable < T > or IEnumerable < T > .

So you'll want to create a type to keep the data.

var myData = from a in db.MyTable
             where a.MyValue == "A"
             select new MyType
             {
                 Key = a.Key,
                 Value = a.MyValue
             };

Answer 2

IQueryable

所以你的方法声明看起来像

public IQueryable GetSomeData()

Answer 3

A generic method should give you intellisense:

public class MyType {Key{get;set;} Value{get;set}}

public IQueryable<T> GetSomeData<T>() where T : MyType, new() 
 { return from a in db.MyTable
          where a.MyValue == "A" 
          select new T {Key=a.Key,Value=a.MyValue};
 }

Answer 4

If you want to return, you need a type.

Instead of var , declare using IEnumerable<> and return that variable. Iterating through it actually executes the query.