For C Language: How to do you Display a growing Series of Numbers using the For Loop per line?

Question

How do you make C use the For Loop Statement and generate this:

1
12
123
1234
12345
123456
1234567
12345678

I know this requires that the value "1" to be continuously be multiplied with "10" and added with "1".

Answer 1

since the sequence ended with 12345678, this loop only goes to 8, if wanted otherwise, the constraints should be changed approriately

int result = 0;
int i;
for(i = 1; i < 9; i++)
{
    result = result * 10 + i;
    printf("%d\n", result);
}

Answer 2

Is this homework?

Use a variable to keep track of the current number. On the next iteration, multiply by ten and add the next number in the series.

#include "stdio.h"
int main() {
    int current = 0;
    int i;
    for (i = 1; i < 10; i++) {
        current = current * 10 + i;
        printf("%d\n", current);
    }
}

Answer 3

As an alternative to using integers to contain the result, you might want to use a character buffer, appending the loop index. If you need 10+, you could mod the index and continue with a repeating sequence for the desired length.

No code given, as it is homework!