I was wondering how can I check if there is no tags entered into the database for a specific post if there are none, display no tags have been entered
. How can I do this using PHP?
Here is my PHP & MySQL code.
$tag = array();
$dbc = mysqli_query($mysqli, "SELECT tags.tag
FROM posts_tags
INNER JOIN tags ON tags.id = posts_tags.tag_id
WHERE posts_tags.post_id = '" . $post_id . "'
GROUP BY tags.tag");
if (!$dbc) {
print mysqli_error($mysqli);
} else {
while($row = mysqli_fetch_array($dbc)){
$tag[] = $row['tag'];
}
}
If the tag array is empty, then there are no tags:
if(empty($tag)){
echo 'no tags have been entered';
}
You could also check for the number of rows returned:
if(mysqli_num_rows($dbc) == 0){
echo 'no tags have been entered.';
}
Use mysqli_num_rows
and code like this:
$tag = array();
$dbc = mysqli_query($mysqli, "SELECT tags.tag
FROM posts_tags
INNER JOIN tags ON tags.id = posts_tags.tag_id
WHERE posts_tags.post_id = '" . $post_id . "'
GROUP BY tags.tag");
if (!$dbc)
{
print mysqli_error($mysqli);
}
elseif(!mysqli_num_rows($dbc))
{
echo "no tags have been entered";
}
else
{
while($row = mysqli_fetch_array($dbc))
{
$tag[] = $row['tag'];
}
print_r($tag);
}
$(".signup_name_image").hide();
var error_signup_name = false;
$(".signup_name").blur(function(){
check_signup_name();
});
function check_signup_name() {
var signup_name = $.trim($('.signup_name').val());
if (signup_name == '' || signup_name.length < 6 || signup_name.length > 50 ) {
$(".signup_name").css({"border":"1px solid #ff0000"});
$(".signup_name_image").show();
$(".signup_name_show").html("• Write Full Name in 6 to 50 alphabets");
**$(".signup_name").focus();**
error_signup_name = true;
} else if (/^[a-zA-Z0-9- ]*$/.test(signup_name) == false){
$(".signup_name").css({"border":"1px solid #ff0000"});
$(".signup_name_image").show();
$(".signup_name_show").html("• Contain invalid character");
**$(".signup_name").focus();**
error_signup_name = true;
}else {
$(".signup_name").css({"border":"1px solid #21cc00"});
$(".signup_name_image").hide();
}
}
$("#signup_form").submit(function(){
error_signup_name = false;
check_signup_name();
if (error_signup_name == false) {
return true;
} else {
return false;
}
});
$(".signup_name_image").hover(function(){
$(".signup_name_show").show();
}, function() {
$(".signup_name_show").hide();}
);
Now Focus is stuck on same field How to Focus on field when submit
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