How does an object reference itself in Javascript?

Question

I was experimenting with inheritance in javascript, and wrote those two functions:

Object.prototype.inherits=function(obj){this.prototype=new obj;}
Object.prototype.pass=function(obj){obj.prototype=new this;}

This code works very well:

Dog.inherits(Animal);

But the following fails:

Animal.pass(Dog);

As I understand it, my pass functions doesn't work, because "this" isn't a reference to the object instance itself? If that's the case, how can I reference the object from within itself?

Thanks in advance!

Answer 1

Well, actually the two are doing exactly the same:

Dog.prototype = new Animal;

The this value inside the methods will refer to the base object where the reference was invoked, in the case of:

Dog.inherits(Animal);

The this value will refer to the Dog constructor function, and the obj argument will be the Animal function.

When you call:

Animal.pass(Dog);

The this value will refer to the Animal function, doing at the end exactly the same thing as the inherits method, but the other way around.

I would recommend you to not extend the Object.prototype object, because it can cause you a lot of problems, for example those two properties will be enumerated in any for-in loop, eg:

for (var prop in {}) { // <-- an empty object!
  alert(prop); // will alert 'inherits' and 'pass'
}

All objects inherit from Object.prototype , and it seems that you intend to use those methods only on Function objects, it would be safer to extend the Function.prototype object, or implement the methods as functions that take two parameters.

Answer 2

Works for me, with test code like:

function Animal() {}
Animal.prototype.isanimal= 1;
function Dog() {}
Animal.pass(Dog);
Dog.prototype.isdog= 2;
alert(new Dog().isanimal); // 1
alert(new Dog().isdog);    // 2

However, bear in mind that new this or new obj will call the function this/obj , creating a new full instance. If you have constructor code in that function that expects to receive some arguments, or sets up instance state, you can end up with problems. To create a new this without calling this as a function you can use a different constructor that does nothing:

function nonconstructor() {}
nonconstructor.prototype= this.prototype;
obj.prototype= new nonconstructor();

Also, you should avoid prototyping onto Object . This will cause trouble for code using Object as a general-purpose lookup map. As you only seem to be working with constructor-functions, prototyping onto Function should meet your needs and is much safer.