简体   繁体   中英

Erroneous ORA-01427: single-row subquery returns more than one row

I'm getting the error [ORA-01427: single-row subquery returns more than one row] when I execute a query. I have a query structured like so:

SELECT LV.PRICE,
 (SELECT C.MODEL_NAME FROM CARS C WHERE C.MODEL_ID = LV.MODEL_ID) as MODEL_NAME
FROM LEDGER_VIEW LV
WHERE LV.PRICE < 500

It's breaking on the nested select. I know the logic both in the view and in this query is correct, and that there's no chance of the nested select returning more than one row. The CARS table's MODEL_ID is a unique field. If I execute the query without the nested select it doesn't return this error.

The LEDGER_VIEW is a view built on top of another view. Is it possible that these stacked views are buggy in Oracle 10g? I don't know how else to debug this problem.

I am aware I could change this particular query to a join rather than a nested select, but I'd like to know why this is happening because I use nested queries in other places where it is not so easily modifiable.

EDIT : Here's the really strange thing. The LEDGER_VIEW is, as I said, built on top of another view. As a test, I copied the nested view's SQL directly into the SQL of the SQL of LEDGER_VIEW, in place of the nested view, and it returned with no errors (as expected). This seems to confirm to me that there is some buggy behavior either with nested views or with the combination of nested views + database links.

Your subquery is returning multiple rows. Use the query below to find out which MODELID values in the Car table are duplicated:

select MODELID as CarsModelID, count(*) as Count
from cars 
where MODELID in (
    select MODEL_ID
    from LEDGER_VIEW  
    WHERE LV.PRICE < 500 
)
group by MODELID
having count(*) > 1

I am unable to recreate via a creation of a stacked view. (althoug RedFilters will find the culprit)

    CREATE TABLE t1
    (
        t1_id NUMBER        ,
        txt   VARCHAR2( 50 ),
        CONSTRAINT t1_pk PRIMARY KEY( t1_id )
    ) ;


    CREATE TABLE t2
    (
        t2_id NUMBER                      ,
        t1_id NUMBER                      ,
        price NUMBER( 10, 4 )             ,
        CONSTRAINT t2_pk PRIMARY KEY( t2_id ),
        CONSTRAINT t2_fk FOREIGN KEY( t1_id ) REFERENCES t1( t1_id )
    );

    insert into t1(t1_id, txt) values(1,'fit');
    insert into t1(t1_id, txt) values(2,'focus');
    insert into t1(t1_id, txt) values(3,'golf');
    insert into t1(t1_id, txt) values(4,'explorer');
    insert into t1(t1_id, txt) values(5,'corolla');

insert into t2(t2_id, t1_id, price) values(1,1,17000);
insert into t2(t2_id, t1_id, price) values(2,2,16000);
insert into t2(t2_id, t1_id, price) values(3,3,22000);
insert into t2(t2_id, t1_id, price) values(4,4,31000);
insert into t2(t2_id, t1_id, price) values(5,5,17000);


create view t1_view as select * from t1;
create view t2_view as select * from t2;
create view t_stacked_view as 
  select t1_view.txt ,
       t2_view.price ,
         t1_view.t1_id
    from t1_view 
          left join
          t2_view 
            on t1_view.t1_id = t2_view .t1_id
    ;   


--stacked view test
select t1_view.txt ,
       (select t_stacked_view.price 
            from t_stacked_view 
             where t1_view.t1_id = t_stacked_view .t1_id) price
    from t1_view ;

--or better yet, just drop the row level query
select t1_view.txt ,
       t2_view.price
    from t1_view 
          left join
          t2_view 
            on t1_view.t1_id = t2_view .t1_id
    ; 

But that begs the question, why are you doing the row level query here? While 10g ought to optimize them the same, I have always found it easier to write queries as below, both for readability, maintainability, and to specifically avoid the error you are having (is it always, 3 years down the road, guaranteed by the application (both in the db and the calling app) that you cannot have a condition that will cause this error? One rouge statement gets in and your entire app dies?

    SELECT LV.PRICE,
            c.model_name
FROM LEDGER_VIEW LV
      LEFT /* OR INNER */ JOIN CARS C 
       ON C.MODEL_ID = LV.MODEL_ID
WHERE LV.PRICE < 500

I suggest using RedFilter's answer to check whether there are multiple cars with a given MODEL_ID.

If you're absolutely certain that CARS.MODEL_ID is unique, then it implies that the error message is generated by selection from LEDGER_VIEW - so try running the equivalent query without the subquery on CARS, like so:

SELECT LV.PRICE
FROM LEDGER_VIEW LV
WHERE LV.PRICE < 500

If you still see the same error (you should, if CARS.MODEL_ID is unique) you will need to debug LEDGER_VIEW - ie. check for sub-queries returning multiple rows in LEDGER_VIEW and the underlying views it is based on.

Creating views based on views is possible in most forms of SQL, but it is usually a bad idea - for this very reason.

select
                                    a.account_number,
                                    a.party_id,
                                    a.TRX_NUMBER,
                                    a.trx_date,
                                    a.order_number,
                                    adv.unapplied_amt,
                                    a.Finance,
                                    a.customer_name,a.PARTY_NAME,
                                    a.customer_number,a.contact_number,
                                    a.name,
                                    a.Aging,
                                    a.transaction_type,
                                    a.exec_name,
                                    a.team_leader,
                                    sum(a.O_SAmount),
                                    (case when (trunc(sysdate) - trunc(a.trx_date)) <=:ag1 then sum(a.O_SAmount) else 0 end ) bucket1,--"<" || :ag1,
                                    (case when (trunc(sysdate) - trunc(a.trx_date)) between :ag1+1 and :ag2 then sum(a.O_SAmount) else 0 end ) bucket2,--:ag1+1 || "to" || :ag2,
                                    (case when (trunc(sysdate) - trunc(a.trx_date)) between :ag2+1 and :ag3 then sum(a.O_SAmount) else 0 end ) bucket3,--:ag2+1 || "to" || :ag3,
                                    (case when (trunc(sysdate) - trunc(a.trx_date)) >:ag3 then sum(a.O_SAmount) else 0 end ) bucket4,
                                    :AS_ON_date
from
(select distinct hca.account_number,hp.party_id,--rcta.CUSTOMER_TRX_ID,
--rcta.trx_number,rcta.trx_date,apsa.due_date,
(
select distinct
                            --ooha.order_number,
                            rcta.trx_number
                            --to_char(rcta.trx_date,'DD-MON-YYYY') trx_date
from                            
                            ra_customer_trx_all rcta,
                            oe_order_headers_all ooh,
                            oe_order_lines_all oola,
                            --ra_customer_trx_all rcta,
                            ra_customer_trx_lines_all rctla,
                            ra_cust_trx_types_all rctta
                            --ra_customer_trx_lines_all rctl
where 1=1
                AND ooh.header_id = oola.header_id
                   --AND ooh.order_number = '111111010101698'
                   AND ooh.order_number=oohA.order_number
                   AND TO_CHAR (ooh.order_number) = rcta.ct_reference
                   AND rcta.customer_trx_id = rctla.customer_trx_id
                   AND rctla.inventory_item_id = oola.inventory_item_id
                   and rcta.CUST_TRX_TYPE_ID = rctta.cust_trx_type_id
                   and rcta.org_id = rctta.org_id
                   and rctta.type like 'INV'
                   and oola.ordered_item LIKE 'MV%' 
                   AND oola.attribute3 = 'Y'
                   AND ooh.flow_status_code <> 'ENTERED'
                   AND oola.flow_status_code <> 'CANCELLED'
)TRX_NUMBER,
(select distinct
--ooha.order_number,
--rcta.trx_number
rcta.trx_date
from
            ra_customer_trx_all rcta,
            oe_order_headers_all ooh,
            oe_order_lines_all oola,
            --ra_customer_trx_all rcta,
            ra_customer_trx_lines_all rctla,
            ra_cust_trx_types_all rctta
            --ra_customer_trx_lines_all rctl
where 1=1
               AND ooh.header_id = oola.header_id
               --AND ooh.order_number = '111111010101698'
               AND ooh.order_number=oohA.order_number
               AND TO_CHAR (ooh.order_number) = rcta.ct_reference
               AND rcta.customer_trx_id = rctla.customer_trx_id
               AND rctla.inventory_item_id = oola.inventory_item_id
               and rcta.CUST_TRX_TYPE_ID = rctta.cust_trx_type_id
               and rcta.org_id = rctta.org_id
               and rctta.type like 'INV'
               and oola.ordered_item LIKE 'MV%' 
               AND oola.attribute3 = 'Y'
               AND ooh.flow_status_code <> 'ENTERED'
               AND oola.flow_status_code <> 'CANCELLED'
)TRX_Date,
rcta.INTERFACE_HEADER_ATTRIBUTE1 order_number,
ooha.attribute10 Finance,
f.customer_name,HP.PARTY_NAME,
TO_NUMBER(f.customer_number)customer_number,hp.primary_phone_number contact_number,--csi.incident_number,
--cii.instance_number,
haou.name,
--sum(acr.amount) Advance,--rcta.CUST_TRX_TYPE_ID,--acr.cash_receipt_id,
--sum(abs((apsa.AMOUNT_DUE_REMAINING-nvl(acr.amount,0)))) "O_SAmount",
apsa.AMOUNT_DUE_REMAINING O_SAmount,
--sum(abs((apsa.AMOUNT_DUE_REMAINING))) "O_SAmount",
round(months_between(sysdate,rcta.trx_date)*30) Aging,
--(case when ((round(months_between(sysdate,rcta.trx_date)*30)>=0) or (round(months_between(sysdate,rcta.trx_date)*30)<:aging1)) then apsa.AMOUNT_DUE_REMAINING end) "0 TO 30"
--(case when (trunc(sysdate) - trunc(apsa.Due_Date)) <=:ag1 then apsa.AMOUNT_DUE_REMAINING else 0 end ) bucket1,--"<" || :ag1,
--(case when (trunc(sysdate) - trunc(apsa.Due_Date)) between :ag1+1 and :ag2 then apsa.AMOUNT_DUE_REMAINING else 0 end ) bucket2,--:ag1+1 || "to" || :ag2,
--(case when (trunc(sysdate) - trunc(apsa.Due_Date)) between :ag2+1 and :ag3 then apsa.AMOUNT_DUE_REMAINING else 0 end ) bucket3,--:ag2+1 || "to" || :ag3,
--(case when (trunc(sysdate) - trunc(apsa.Due_Date)) >:ag3 then apsa.AMOUNT_DUE_REMAINING else 0 end ) bucket4,
--apsa.amount_due_original,
--TO_NUMBER(apsa.AMOUNT_DUE_REMAINING)AMOUNT_DUE_REMAINING,
rctta.name transaction_type,
PAPF.full_name||'-'||PAPF.EMPLOYEE_NUMBER exec_name,
ooha.attribute9 team_leader,
:AS_ON_date
from                    ra_customer_trx_all rcta,
                        oe_order_headers_all ooha,
                        hz_cust_accounts hca,
                        hz_parties hp,
                        --cs_incidents_all_b csi,
                        --csi_item_instances cii,
                        hr_all_organization_units haou,
                        ar_cash_receipts_all acr,
                        ar_receivable_applications_all aaa,
                        ra_cust_trx_types_all RCTTA,
                        hr.per_all_people_f papf,
                        ar_customers f,
                        ar_payment_schedules_all apsa,
                        jtf.JTF_RS_SALESREPS jrs
where 1=1
                        --and INTERFACE_HEADER_ATTRIBUTE1 like '111111060100538'
                        --and INTERFACE_HEADER_ATTRIBUTE1 like '111111010105402'
                        --and INTERFACE_HEADER_ATTRIBUTE1 like '111111010102791'
                        and rcta.ct_reference(+)=TO_CHAR(ooha.order_number)
                        AND f.customer_id = (rcta.bill_to_customer_id) 
                        and f.customer_id=hca.cust_account_id
                        and hca.party_id=hp.party_id
                        and haou.organization_id=rcta.INTERFACE_HEADER_ATTRIBUTE10
                        --and hp.party_id=cii.owner_party_id
                        --and csi.inventory_item_id=cii.inventory_item_id
                        --and csi.inv_organization_id=haou.organization_id
                        --and haou.organization_id=nvl(:location,haou.organization_id)
                        and ooha.SHIP_FROM_ORG_ID=nvl(:location,haou.organization_id)
                        AND RCTTA.NAME like :transaction_type||'%'
                        --decode(:org_id,null,null,(select name from ar_cash_receipts_all where organization_id = :org_id)) ||'%')
                        and rcta.trx_date<=to_date(:AS_ON_date)
                        --AND RCTTA.NAME=NVL(:TRANS_TYPE,RCTTA.NAME)
                        and rcta.org_id=nvl(:org_id,rcta.org_id)
                        --and f.customer_name like 'VIKAS SATAV'
                        and aaa.applied_customer_trx_id(+)=rcta.customer_trx_id
                        and aaa.cash_receipt_id=acr.cash_receipt_id(+)
                        and rcta.status_trx like 'OP'
                        and rcta.CUST_TRX_TYPE_ID=rctta.CUST_TRX_TYPE_ID
                        and apsa.CUSTOMER_TRX_ID=rcta.CUSTOMER_TRX_ID
                        and TO_NUMBER(apsa.AMOUNT_DUE_REMAINING) >0
                        --and hp.party_id=papf.party_id(+)
                        and jrs.salesrep_id = ooha.SALESREP_ID
                        and jrs.ORG_ID = ooha.ORG_ID
                        and jrs.PERSON_ID = papf.PERSON_ID(+)
) a,
(
select
b.order_number,
sum(b.AMOUNT_APPLIED) unapplied_amt
from
                        (select distinct to_char(ooha.order_number) order_number,ara.* from 
                        oe_order_headers_all ooha,
                        oe_payments oe,
                        ar_receivable_applications_all ara
where                    1=1--ooha.order_number = :p_order_num
                        and oe.header_id=ooha.header_id
                        and ara.PAYMENT_SET_ID=oe.PAYMENT_SET_ID
                        and ara.DISPLAY='Y'
                        and (ara.STATUS like 'OTHER ACC' or ara.STATUS like 'UNAPP') --or ara.STATUS like 'ACC')
                        ) b
group by b.order_number
) adv
where                       adv.order_number(+)=a.order_number
group by                    a.account_number,
                            a.party_id,
                            a.TRX_NUMBER,
                            a.trx_date,
                            a.order_number,
                            adv.unapplied_amt,
                            a.Finance,
                            a.customer_name,a.PARTY_NAME,
                            a.customer_number,a.contact_number,
                            a.name,
                            a.Aging,
                            a.transaction_type,
                            a.exec_name,
                            a.team_leader
order by a.Aging desc

Try forcing your subquery to return a single result by appending rownum = 1, like this:

SELECT LV.PRICE,
(SELECT C.MODEL_NAME FROM CARS C WHERE C.MODEL_ID = LV.MODEL_ID AND ROWNUM = 1) as MODEL_NAME
FROM LEDGER_VIEW LV
WHERE LV.PRICE < 500

It will probably work and if it does, you will know that your subquery returns multiple rows, which judging by the error code it should be. Of course this is not a solution so you might have to fix your data in cars table to actually solve the problem. Leaving and rownum = 1 will eliminate the error if model_id is duplicated again, preventing you from noticing the problem.

The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM