Typedef struct question

Question

Why would I want to do this?

typedef struct Frame_s
{
int x;
int y;
int z;
} Frame_t;

Also if I want to create an object what do I use Frame_s or Frame_t?

Answer 1

You would use Frame_t .

With typedef you are saying that Frame_t and struct Frame_s are the exact same type .

So these are equivalent sentences:

// 1
Frame_t f;

// 2
struct Frame_s f;

I would use:

typedef struct
{
   int x;
   int y;
   int z;
} Frame_t;

And always declare my vars like this:

Frame_t f1, f2, f3;

Confusion usually comes from places where you use that sentence in a C++ piece of code. If you use C++ with that typedef you can use either:

// 1
Frame_t f;

// 2
Frame_s f;

But if you use a plain C compiler, then //2 is invalid.

Answer 2

Either you use struct Frame_s , or you use Frame_t .

Usually you do such a typedef so that you can use the typedefed name, Frame_t , and don't have to write struct whenever you refer to the type.

Aside from Frame_t being shorter than struct Frame_s there is no real difference.

Answer 3

Another aspect of typedef that has not yet been mentioned in the other replies is that it reserves the identifier and thus may avoid confusion. If you do a forward declaration like that

typedef struct Frame Frame;

you would avoid that some code that may use the same name Frame eg a variable or function.

One very bad traditional example that comes in mind for this is "sys/stat.h" in POSIX: it defines a struct stat and a function stat :

int stat(const char *path, struct stat *buf);

Answer 4

To declare a value of the struct, you could use either struct Frame_s foo or Frame_t foo (the latter is more normal, since that's the whole point of typedefing). My guess is that Frame_s is meant to indicate the struct type itself, while Frame_t is the plain type that's normally used for Frame values.

Answer 5

typedef is used as a short form. So when a function which returns a structure of this type, normally you write -

struct Frame_s *function_name()

The code start to get obfuscated. Function definitions become long etc. With this typedef you get -

Frame_t *function_name()

Clean code! Makes a big difference in maintenance...

Answer 6

So these two declarations are equivalent:

struct Frame_s f;
Frame_t f;

In fact, you could now leave Frame_s out of the declaration as it isn't needed.

typedef struct
{
  int x;
  int y;
  int z;
} Frame_t;