shell_exec php example

Question

Hi there are multiple specific examples but I just wanted to have a working generic calling PHP into background example from shell_exec.

So my php function runs a large processing job.

On the top of the script (process.php) I put?

!#usr/bin/php

i think - any way to get that specific path, maybe 'which php'?

then the actual command is

shell_exec(sprintf('php process.php %s %s > /dev/null 2>/dev/null &','data1','data2'));

and access the data from process.php with argsv[1] and argsv[2]

?

thanks

Answer 1

您需要使用参数在PHP脚本上运行curl multi exec ，并在运行后收到答案，例如： http://localhost/phpjob.php?par1=asdasd&par2=1212....

Answer 2

You can definitely access the arguments from process.php the way you described, but why would you want to kick off process.php like that?

If you're already in a php shell script, why not just include the process.php file?